如何用C实现万年历HTML代码

C实现万年历

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define str ” SUN MON TUE WED THU FRI SAT ”

void menu(); //操作菜单
int leap(int year); //判断某年是不是闰年
int days_month(int year, int month); //返回某月的天数
int someday(int year, int month, int day); //计算某天是星期几
void search_month(int year, int month); //输出某月的日历
void search_someday(int year, int month, int day); //查询某日是星期几

int main()
{
int i, year, month, day;
int k1, k2, k3, k4; //用于判断输入的数据和操作是否正确,1代表正确,0代表错误
int a = 1;
menu();
do
{
printf(“请输入你要进行的操作(1-4):”);
scanf_s(“%d”, &i);
getchar();
switch (i)
{
case 1:
printf(“请输入你要查询的年份:”); scanf_s(“%d”, &year);
for (a; a <= 12; a++)
{
printf(“\n\n———******* %d *******————\n”, a);
search_month(year, a);
}
printf(“———*********************————\n\n\n”);
break;

case 2:
printf(“请输入您所要查询的相关信息.\n”);
printf(“年份:”); scanf_s(“%d”, &year);
printf(“月份:”); scanf_s(“%d”, &month);
k1 = 1;
while (k1)
{
if (month > 12 || month < 1)
{
printf(“你输入的月份有误,请重新输入!\n”);
printf(“月份:”);
scanf_s(“%d”, &month);
if (month < 1 || month>12) k1 = 1;
}
else k1 = 0;
}
search_month(year, month);
printf(“———*********************————\n\n\n”);
break;

case 3:
printf(“请输入你要查询的日期\n”);
printf(“年份:”); scanf_s(“%d”, &year);
printf(“月份:”); scanf_s(“%d”, &month);
k2 = 1;
while (k2)
{
if (month > 12 || month < 1)
{
printf(“你输入的月份有误,请重新输入!\n”);
printf(“月份:”);
scanf_s(“%d”, &month);
if (month < 1 || month>12) k2 = 1;
}
else k2 = 0;
}
// printf(“%d年%d月有%d天\n”,year,month,days_month(year,month)); 调试观察输入的日期是否有误,可忽略
printf(“日期:”); scanf_s(“%d”, &day);
k3 = 1;
while (k3)
{
if (day > days_month(year, month) || day < 1)
{
printf(“你输入的日期有误,请重新输入!\n”);
printf(“日期:”);
scanf_s(“%d”, &day);
if (day > days_month(year, month) || day < 1) k3 = 1;
}
else k3 = 0;
}
search_someday(year, month, day);
printf(“———*********************————\n\n\n”); break;

case 4:exit(0);
printf(“———*********************————\n\n\n”); break;

default:
k4 = 1;
while (k4)
{
printf(“你输入的数据有误,请重新输入你要进行的操作(1-4):”);
scanf_s(“%d”, &i);
if (i < 1 || i>4) k4 = 1;
else k4 = 0;
}
break;
}
} while (i > 0 && i < 5);
return 0;
}

void menu()
{
int i = 1;
printf(“\n\n\t\t—————————————-\n”);
printf(“\t\t|————————————–|\n”);
printf(“\t\t| %d. 输出某年的日历 |\n”, i);
printf(“\t\t| %d. 输出某月的日历 |\n”, i + 1);
printf(“\t\t| %d. 查询某日是星期几 |\n”, i + 2);
printf(“\t\t| %d. 退出系统 |\n”, i + 3);
printf(“\t\t|————————————–|\n”);
printf(“\t\t—————————————-\n\n”);

}

int leap(int year)
{
if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) return 1;
else return 0;
}

int days_month(int year, int month)
{
int days_month;
switch (month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12: days_month = 31; break;

case 4:
case 6:
case 9:
case 11:days_month = 30; break;

case 2:
if (leap(year) == 1)
{
days_month = 29; break;
}
else days_month = 28; break;
}
return days_month;
}

int someday(int year, int month, int day)
{
//该函数运用了特殊的计算公式,详细可参见 http://blog.163.com/hexin_mars_blog/blog/static/248215040201571351115699/
int someday, m, n, i; //someday表示查询的日子是星期几
m = year – year / 1000 * 1000;
n = m – m / 100 * 100 – 1; //用于获得年份的后两位数
int days = 0;
for (i = 1; i < month; i++) days = days + days_month(year, i);
days = days + day;
someday = (n + n / 4 – n / 100 + n / 400 + days) % 7;
return someday;
}

void search_someday(int year, int month, int day)
{
char weekname[20];
switch (someday(year, month, day))
{
case 0:strcpy_s(weekname, “星期天”); break;
case 1:strcpy_s(weekname, “星期一”); break;
case 2:strcpy_s(weekname, “星期二”); break;
case 3:strcpy_s(weekname, “星期三”); break;
case 4:strcpy_s(weekname, “星期四”); break;
case 5:strcpy_s(weekname, “星期五”); break;
case 6:strcpy_s(weekname, “星期六”); break;
}
printf(“你所要查询的日期是%s\n”, weekname);
}

void search_month(int year, int month)
{
int i = 0, j, k = 0, m; //j用于记录某月的第一天是星期几 m用于记录某月的天数 k用于换行提示
char x[10] = ” “;
m = days_month(year, month);
j = someday(year, month, 1);

//输出某月的日历
printf(“——————————————\n”);
printf(“%s\n”, str);
for (; i < j; i++)
{
printf(“%s”, x); k++;
}
for (i = 1; i <= m; i++)
{
k++;
if (k % 7 == 0)
{
if (i < 10)
{
printf(” %d “, i);
printf(“\n”);
}
else if (i >= 10)
{
printf(” %d “, i);
printf(“\n”);
}
}
else
{
if (i < 10)
{
printf(” %d “, i);
}
else if (i >= 10)
{
printf(” %d “, i);
}
}
}
printf(“\n——————————————\n”);
}

void exit()
{
exit(0);
}

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